F(x+7)=x^2+8x-4

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Solution for F(x+7)=x^2+8x-4 equation:



(F+7)=F^2+8F-4
We move all terms to the left:
(F+7)-(F^2+8F-4)=0
We get rid of parentheses
-F^2+F-8F+7+4=0
We add all the numbers together, and all the variables
-1F^2-7F+11=0
a = -1; b = -7; c = +11;
Δ = b2-4ac
Δ = -72-4·(-1)·11
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{93}}{2*-1}=\frac{7-\sqrt{93}}{-2} $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{93}}{2*-1}=\frac{7+\sqrt{93}}{-2} $

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